Show that the equation {x^2} + {y^2} - 4x + 6y - 5 = 0 represents a circle. Find its centre and radius.
Show that the equation {x^2} + {y^2} - 4x + 6y - 5 = 0 represents a circle. Find its centre and radius.

Answer:

The general equation of a conic is,

ax2 + 2hxy + by2 + 2gx + 2fy + c = 0

a, b, c, f, g, h are constants

For a circle, a = b and h = 0.

The equation is,

x2 + y2 + 2gx + 2fy + c = 0

x2 + y2 – 4x + 6y – 5 = 0

The equation represents a circle with 2g = – 4

g = – 2, 2f = 6

f = 3 and c = – 5

Centre ( – g, – f)

=> { – ( – 2), – 3}

=> (2, – 3).

\begin{array}{l}  Radius = \sqrt {{g^2} + {f^2} - c} \\  =  > \sqrt {{{( - 2)}^2} + {3^2} - ( - 5)} \\  =  > \sqrt {4 + 9 + 5} \\  =  > \sqrt {18} \\  =  > 3\sqrt 2  \end{array}