Answer:
Let the smallest term be x, and the largest term be 2x
Then AP formed= x, ?, ?, 2x
so,
360°= 4/2 [x+ 2x]….[We know that → a+(n-1) d= last term= 2x]
⇒ 180°= 3x
⇒ x= 60°
Now, 60° is least angle.
= 60°= π/180° × 60°
⇒ 60° = π/3 rad
The angles of a quadrilateral are in AP, and the greatest angle is double the least. Express the least angle in radians.
The angles of a quadrilateral are in AP, and the greatest angle is double the least. Express the least angle in radians.