The mean free path for a gas, with molecular diameter d and number density n can be expressed as : (1) \frac{1}{\sqrt{2} n^{2} \pi d^{2}} (2) \frac{1}{\sqrt{2} n^{2} \pi^{2} d^{2}} (3) \frac{1}{\sqrt{2} n \pi d } (4) \frac{1}{\sqrt{2} n \pi d^{2}}
The mean free path for a gas, with molecular diameter d and number density n can be expressed as : (1) \frac{1}{\sqrt{2} n^{2} \pi d^{2}} (2) \frac{1}{\sqrt{2} n^{2} \pi^{2} d^{2}} (3) \frac{1}{\sqrt{2} n \pi d } (4) \frac{1}{\sqrt{2} n \pi d^{2}}

Correct option: 4)

In physics, the mean free path is the average distance over which a moving particle’s direction or energy changes significantly, usually as a result of one or more successive collisions with other particles.

The mean free path for gas is given by \lambda=\frac{1}{\sqrt{2} \pi nd ^{2}}