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Home » The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of . If the piston moves with simple harmonic motion with an angular frequency of , what is its maximum speed?
The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 \mathrm{~m}. If the piston moves with simple harmonic motion with an angular frequency of \mathbf{2 0 0} \mathbf{~ r a d} / \mathrm{min}, what is its maximum speed?
CBSE | Class 11 | NCERT | Oscillations | Physics
The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 \mathrm{~m}. If the piston moves with simple harmonic motion with an angular frequency of \mathbf{2 0 0} \mathbf{~ r a d} / \mathrm{min}, what is its maximum speed?

Angular frequency of the piston is given as \omega=200 \mathrm{rad} / \mathrm{min}

Stroke is given as=1.0 \mathrm{~m}

Amplitude is given as A=1.0 / 2

=0.5 \mathrm{~m}

The maximum speed \left(v_{\max }\right) of the piston can be calculated as,

V_{\max }=A \omega

=200 \times 0.5

We get,

=100 \mathrm{~m} / \mathrm{min}

As a result, its maximum speed is 100 \mathrm{~m} / \mathrm{min}

i

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