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Home » The value of gravitational acceleration ‘ ‘ at a height ‘h’ above the earth’s surface is then radius of earth)A) B) C) D)
The value of gravitational acceleration ‘ \mathrm{g} ‘ at a height ‘h’ above the earth’s surface is \frac{\mathrm{g}}{4} then (\mathrm{R}= radius of earth)
A) h=R
B) \mathrm{h}=\frac{\mathrm{R}}{2}
C) \mathrm{h}=\frac{\mathrm{R}}{3}
D) \mathrm{h}=\frac{\mathrm{R}}{4}
Physics
The value of gravitational acceleration ‘ \mathrm{g} ‘ at a height ‘h’ above the earth’s surface is \frac{\mathrm{g}}{4} then (\mathrm{R}= radius of earth)
A) h=R
B) \mathrm{h}=\frac{\mathrm{R}}{2}
C) \mathrm{h}=\frac{\mathrm{R}}{3}
D) \mathrm{h}=\frac{\mathrm{R}}{4}

Answer is (A)
g^{\prime}=g\left(\frac{R}{R+h}\right)^{2}
When g^{\prime}=\frac{g}{4} then.
\begin{array}{l} \frac{g}{4}=g \times\left(\frac{R}{R+h}\right)^{2} \Rightarrow \frac{1}{2}=\frac{R}{R+h} \\ \therefore 2 R=R+h \Rightarrow R=h \end{array}

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