Two discs of moments of inertia I_{1} and I_{2} about their respective axes and rotating with angular speed \omega_{1} and \omega_{2} are brought into contact face to face with their axes of rotation coincident.
a) calculate the loss in kinetic energy of the system in the process
b) account for this loss
Two discs of moments of inertia I_{1} and I_{2} about their respective axes and rotating with angular speed \omega_{1} and \omega_{2} are brought into contact face to face with their axes of rotation coincident.
a) calculate the loss in kinetic energy of the system in the process
b) account for this loss

a) Final kinetic energy = rotational + translation energy

K_{f}=KE_{R}+KE_{T}

\Delta \mathrm{K}=-I_{1} l_{2} / 2\left(I_{1}+l_{2}\right)\left(\omega_{1}-\omega_{2}\right) 2<0

b) Because energy is lost during friction between moving surfaces, K_{f}<K_{i}