Solution:-

(i) We have to find the value of 2 sin θ – cos θ

From the question it is given that, value of θ = 35^o

So, substitute the value of θ,

= 2 sin 35^o – cos 35^o

From the table value of sin 35^o = .5736 and cos 35^o = .8192

= (2 × .5736) – .8192

= 0.3280

(ii) from the question it is given that, tan θ = .2679

In the table of natural sines, look for a value (≤ .2679) which is sufficiently close to .2679.

We find the value column headed by 15^o.

So we get, θ = 15^o

So, substitute the value of θ,

= 2 sin 15^o – cos 15^o

From the table value of sin 15^o = .2588 and cos 15^o = .9659

= (2 × .2588) – .9659

= -0.4483