What is the stopping potential, when a metal surface with work function 1.2 \mathrm{eV} is illuminated with light of energy 3 \mathrm{eV} ?
A) 2V
B)1 \cdot 2 \mathrm{~V}
C)1 \cdot 4 \mathrm{~V}
D)1.8 \mathrm{~V}
What is the stopping potential, when a metal surface with work function 1.2 \mathrm{eV} is illuminated with light of energy 3 \mathrm{eV} ?
A) 2V
B)1 \cdot 2 \mathrm{~V}
C)1 \cdot 4 \mathrm{~V}
D)1.8 \mathrm{~V}

Correct option is D.

\begin{array}{l} e V s=E-W_{0} \\ \therefore V_{s}=\frac{E}{e}-\frac{W_{0}}{e}=\frac{3 e}{e}-\frac{1.2 e V}{e}=1.8 V \end{array}