Which term of the sequence 24, 23 ¼, 22 ½, 21 ¾ is the first negative term?
Which term of the sequence 24, 23 ¼, 22 ½, 21 ¾ is the first negative term?

Answer:

Given,

AP of 24, 23 ¼, 22 ½, 21 ¾, … = 24, 93/4, 45/2, 87/4, …

a1 = a = 24

a2 = 93/4

Common difference,

d = a2 – a1 = 93/4 – 24

= (93 – 96)/4

= – 3/4

an = a + (n – 1) d

an = a + (n – 1) d

an = 24 + (n – 1) (-3/4)

= 24 – 3/4n + ¾

= (96+3)/4 – 3/4n

= 99/4 – 3/4n

Put, an < 0

an = 99/4 – 3/4n < 0

99/4 < 3/4n

3n > 99

n > 99/3

n > 33

34th term is the first negative term of given AP.