As per the question it is given that, a coin is tossed twice.
As we all know that, coin has two faces one is head and other one is tail.
The possibilities of getting head and tail when a coin is tossed twice = {HH, TT, HT, TH}
Total number of outcomes
(i)
The probability that getting no head,
Number of favorable outcomes
P(getting no head) = Number of favorable outcomes/total number of Outcomes
(ii)
The probability that getting at most tail,
Number of favorable outcomes
P(getting at most tail) = Number of favorable outcomes/total number of Outcomes