Solution:-
Steps of construction:
1. Draw a line segment .
2. Then draw its perpendicular bisector which intersects BC at D.
3. With D as a center and BD or CD radius, draw a semi-circle.
4. Now produce the perpendicular bisector of BC which intersects the circle at A
5. Join AB and AC, so is the required isosceles right angled triangle.
Therefore, perpendicular bisector hypotenuse BC is the lines of symmetry of isosceles right angled triangle.