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Home » 9. Construct a in which , PQ = 5.2 cm and QR = 2.6 cm. Complete the figure taking PR as the line of symmetry and name the figure.
9. Construct a \Delta PQR in which \angle R=90{}^\circ , PQ = 5.2 cm and QR = 2.6 cm. Complete the figure taking PR as the line of symmetry and name the figure.
CBSE | Class 10 | Class 10 | Frank | Maths | Symmetry
9. Construct a \Delta PQR in which \angle R=90{}^\circ , PQ = 5.2 cm and QR = 2.6 cm. Complete the figure taking PR as the line of symmetry and name the figure.

Solution:-

Steps of construction:

1. Draw a line segment QS = 2.6 cm.

2. With Q as a center and radius 5.2 cm, draw an arc.

3. At R draw a perpendicular to QR to meet at P.

4. Join PQ, so PQR is the required triangle.

As per the condition given in the question,

5. Taking PR as the line of symmetry.

6. Now, produce QR to S i.e. RS = 2.6 cm

7. With Q as a center and radius 5.2 cm, draw an arc at p.

8. Join PS, so PRS is the triangle.

Therefore,  \Delta PQS is the required triangle and also it is an equilateral triangle.

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