A bag contains 1.0 white and 15 black balls. Two balls are drawn in succession without replacement. What is the probability that the first ball is white and the second is black?
A bag contains 1.0 white and 15 black balls. Two balls are drawn in succession without replacement. What is the probability that the first ball is white and the second is black?

Let, success in the first draw be getting a white ball.
Now, the Probability of success in the first trial is
\mathrm{P}_{1}(\text { success })=\frac{10}{25}
Let success in the second draw be getting a black ball.
Probability of success in the second trial without replacement of the first draw is given by
\mathrm{P}_{2}(\text { success })=\frac{15}{24}
Hence, the probability that the first ball is drawn is white and the second ball drawn is black, with each trial being independent is given by
\mathrm{P}_{1} \times \mathrm{P}_{2}=\frac{10}{25} \times \frac{15}{24}=\frac{1}{4}