1. Give the technical terms of the solutions used in the beakers 1, 2 and 3.
2. In beaker 3, the size of the potato cube remains the same. Explain the reason in brief.
3. Write the specific features of the cell sap of root hair which helps in absorption of water.
4. What is osmosis?
5. How does a cell wall and a cell membrane differ in their permeability?
Answers:
1. Beaker 1 – Hypotonic solution
Beaker 2 – Hypertonic solution
Beaker 3 – Isotonic solution
2. In beaker 3, the size of the potato cube remains the same because the solution available in beaker 3 is an isotonic solution. Equal filtration of water molecules and solute on each side of the cell membrane is similar. In such a solution no movement of external water molecules will enter the cell.
3. Root hairs are extensions of external root cells and also contains large vacuoles filled with a solution called sap.
4. The movement of water molecules from their region of higher concentration to their region of lower concentration through a semi-permeable membrane is called as osmosis.
5.
| Cell wall | Cell membrane |
| Cell wall is thin, permeable and also allows the movement of water molecules and other substances independently inside and outside of the cell. | Cell membrane is thin, semi-permeable and it allows water molecules to pass through in and out of the cells except larger molecules of the dissolved salts. |
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