Given diameter of the cylindrical part of tent, d = 24 m

Radius, r = d/2 = 24/2 = 12 m

Height of the cylindrical part, H = 11 m

Since vertex of cone is 16 m above the ground, height of cone, h = 16-11

h = 5 m

Slant height of the cone, l = √(h²+r²)

l = √(5²+12²)

l = √(25+144)

l = √(169)

l = 13 m

Radius of cone, r = 12 m

Area of canvas used to make the tent = curved surface area of the cylindrical part + curved surface area of the cone.

Area of canvas used to make the tent = 2rH+rl

= r(2H+l)

= (22/7)×12×(2×11+13)

= (264/7)×(22+13)

= (264/7)×35

= 264×5

= 1320 m²

Hence the area of canvas used to make the tent is 1320 m² .