A coin is tossed 6 times. Find the probability of getting at least 3 heads.

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A coin is tossed 6 times. Find the probability of getting at least 3 heads.

As the coin is tossed 6 times the total number of outcomes will be $2^{6}$ .
And we know that the favourable outcomes of getting at least 3 heads will be ${ }^{6} c_{3}+{ }^{6} c_{4}+{ }^{6} c_{5}+{ }^{6} c_{6}$ , Thus, the probability of getting at least 3 heads will be
$=\frac{\text { The favourable outcomes }}{\text { The total number of outcomes }}$
$\Rightarrow\frac{\left(\begin{array}{c}6 \\ 3\end{array}\right)+\left(\begin{array}{c}6 \\ 4\end{array}\right)+\left(\begin{array}{c}6 \\ 5\end{array}\right)+\left(\begin{array}{c}6 \\ 6\end{array}\right)}{2^{6}}$
$\Rightarrow\frac{21}{32}$