A company manufactures two types of sweaters: type A and type B. It costs Rs 360 to make a type A sweater and Rs 120 to make a tvpe B sweater. The companv can make at most 300 sweaters and spend at most Rs 72000 a day. The number of sweaters of type B cannot exceed the number of sweaters of type A by more than 100 . The company makes a profit of Rs 200 for each sweater of type A and Rs 120 for every sweater of type B. Formulate this problem as a LPP to maximize the profit to the company.
A company manufactures two types of sweaters: type A and type B. It costs Rs 360 to make a type A sweater and Rs 120 to make a tvpe B sweater. The companv can make at most 300 sweaters and spend at most Rs 72000 a day. The number of sweaters of type B cannot exceed the number of sweaters of type A by more than 100 . The company makes a profit of Rs 200 for each sweater of type A and Rs 120 for every sweater of type B. Formulate this problem as a LPP to maximize the profit to the company.

Solution:

Suppose \mathrm{x} and \mathrm{y} to be the number of sweaters of type \mathrm{A} and type \mathrm{B} respectively.

The following constraints are:

360 x+120 y \leq 72000 \Rightarrow 3 x+y \leq 600 \ldots (i)

x+y \leq 300 \ldots (ii)

x+100 \geq y \Rightarrow y \leq x+100 \ldots (iii)

Profit: \mathrm{Z}=200 \mathrm{x}+120 \mathrm{y}

So, the required LPP to maximize the profit is

Maximize Z=200 x+120 y subject to constrains

3 x+y \leq 600, x+y \leq 300, y \leq x+100, x \geq 0, y \geq 0