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Home » A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (shown in the adjoining figure) and these are equally likely outcomes. What is the probability that it will point at (i) 8 ? (ii) an odd number ?
A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (shown in the adjoining figure) and these are equally likely outcomes. What is the probability that it will point at
(i) 8 ?
(ii) an odd number ?
CBSE | Class 10 | Exercise 1 | maths | Maths | ML Aggarwal | Probability
A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (shown in the adjoining figure) and these are equally likely outcomes. What is the probability that it will point at
(i) 8 ?
(ii) an odd number ?

Solution:

The possible outcomes of the game are {1,2,3,4,5,6,7,8}

Number of possible outcomes = 8

(i) Let E be the event of arrow pointing 8.

Outcomes favourable to E is 8.

Number of favourable outcomes = 1

P(E) = 1/8

Hence the probability of arrow pointing 8 is 1/8.

(ii) Let E be the event of arrow pointing at odd number.

Outcomes favourable to E is {1,3,5,7}

Number of favourable outcomes = 4

P(E) = 4/8 = 1/2

Hence the probability of arrow pointing at odd number is ½.

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