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Home » A ladder is placed in such a way that its foot is at a distance of 15m from a wall and its top reaches a window 20m above the ground. Find the length of the ladder.
A ladder is placed in such a way that its foot is at a distance of 15m from a wall and its top reaches a window 20m above the ground. Find the length of the ladder.
CBSE | Class 10 | Exercise 4D | Maths | RS Aggarwal | Triangles
A ladder is placed in such a way that its foot is at a distance of 15m from a wall and its top reaches a window 20m above the ground. Find the length of the ladder.

 

 

 

Answer:

Let the height of the window from the ground and the distance of the foot of the ladder from the wall be AB and BC,

AB = 20 m

BC = 15 m

Applying Pythagoras theorem in right-angled ABC,

A C^{2}=A B^{2}+B C^{2}

A C=\sqrt{20^{2}+15^{2}}

A C=\sqrt{400+225}

A C=\sqrt{625}

A C=25 \mathrm{~m}

The length of the ladder is 25 m.

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