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Home » A man arranges to pay off debt of ₹36000 by 40 monthly instalments which form an arithmetic series. When 30 of the installments are paid, he dies leaving on-third of the debt unpaid. Find the value of the first instalment.
A man arranges to pay off debt of ₹36000 by 40 monthly instalments which form an arithmetic series. When 30 of the installments are paid, he dies leaving on-third of the debt unpaid. Find the value of the first instalment.
Arithmetic Progression | CBSE | Class 10 | Maths | RS Aggarwal
A man arranges to pay off debt of ₹36000 by 40 monthly instalments which form an arithmetic series. When 30 of the installments are paid, he dies leaving on-third of the debt unpaid. Find the value of the first instalment.

Solution:

Let the first installment’s value be ₹a.
Let us assume that the man increases the value of each installment by ₹d every month because the monthly installments constitute an arithmetic series.
The arithmetic series’ common difference Equals ₹d

i

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