A nucleus of uranium decays at rest into nuclei of thorium and helium. Then: (1) The helium nucleus has less kinetic energy than the thorium nucleus (2) The helium nucleus has more kinetic energy than the thorium nucleus (3) The helium nucleus has less momentum then the thorium nucleus. (4) The helium nucleus has more momentum than the thorium nucleus - Noon Academy

A nucleus of uranium decays at rest into nuclei of thorium and helium. Then: (1) The helium nucleus has less kinetic energy than the thorium nucleus (2) The helium nucleus has more kinetic energy than the thorium nucleus (3) The helium nucleus has less momentum then the thorium nucleus. (4) The helium nucleus has more momentum than the thorium nucleus

Physics | Physics

A nucleus of uranium decays at rest into nuclei of thorium and helium. Then: (1) The helium nucleus has less kinetic energy than the thorium nucleus (2) The helium nucleus has more kinetic energy than the thorium nucleus (3) The helium nucleus has less momentum then the thorium nucleus. (4) The helium nucleus has more momentum than the thorium nucleus

The correct Solution is (2)
$\begin{array}{l} \mathrm{U} \rightarrow \mathrm{Th}+\alpha \\ \mathrm{KE}_{\mathrm{Th}}=\frac{\mathrm{P}^{2}}{2 \mathrm{~m}_{\mathrm{Th}}}, \mathrm{KE}_{\alpha}=\frac{\mathrm{P}^{2}}{2 \mathrm{~m}_{\alpha}} \end{array}$
Since $\mathrm{m}_{\mathrm{a}}$ is less so $\mathrm{KE}_{\mathrm{a}}$ will be mone.

i

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