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Home » A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
Physics | Physics
A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

(1)\,\,\frac{\sqrt{5}}{2\pi }

(2)\,\,\frac{4\pi }{\sqrt{5}}

(3)\,\,\frac{2\pi }{\sqrt{3}}

(4)\,\,\frac{\sqrt{5}}{\pi }

Solution: Answer (2)

i

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