A piece of iron is heated in a flame. It first become dull red then becomes reddish yellow and finally turns to white hot. The correct explanation for the above observation is possible by using:- Noon Academy

Home » A piece of iron is heated in a flame. It first become dull red then becomes reddish yellow and finally turns to white hot. The correct explanation for the above observation is possible by using:-

A piece of iron is heated in a flame. It first become dull red then becomes reddish yellow and finally turns to white hot. The correct explanation for the above observation is possible by using:-

Physics | Physics

A piece of iron is heated in a flame. It first become dull red then becomes reddish yellow and finally turns to white hot. The correct explanation for the above observation is possible by using:-

Option A Newton’s law of cooling
Option B Stefan’s law
Option C Wien’s law
Option D Kirchhoff’s law

Solution:

The correct option is Option C.

Temperature and wavelength are connected, according to Wien’s displacement law λmT = constant. As a result, it can accurately respond to the previous observation. The black body radiation curve for different temperatures peaks at a wavelength that is inversely proportional to the temperature, according to Wien’s displacement law.

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More Material

The refractive index of glass is $1.5$ . What is the speed of light in glass? Speed of light in vacuum is $3.0 \times 10^{\mathrm{A}} \mathrm{ms}^{-1}$ .

Consider interference between two sources of intensities I and 4I. What will be the intensity at points where phase differences are:

Write two points of difference between interference and diffraction.

State whether the following is true or false: The magnetic field inside a long circular coil carrying current will be parallel straight lines.

A galvanometer with resistance $100 \Omega$ gives full scale deflection with a current of $10 \mathrm{~mA}$ . The value of shunt, in order to convert it into an ammeter of 10 ampere range, will be
A $-10 \Omega$
B $1 \Omega$
C $0.1 \Omega$
D $0.01 \Omega$

Derive an expression for electric potential at a point due to an electric dipole. Discuss the special cases.

Derive an expression for the potential at a point due to a short dipole. Hence show what will be the potential at an axial and an equatorial point :

Find out the wavelength at which a black body at temperature $700 \mathrm{~K}$ emits maximum energy

Name the type of lens which is used to correct? i) Myopia ii) Hypermetropia.

How does concave lens correct myopia?
A Increases the curvature of the eye lens
B Forms the image of the object at the retina
C Decreases the elongation of the eyeball
D All of the above Correct option is (B) Forms the image of the object at the retina

Explain end-on position and broad side-on position of a bar magnet.

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