A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface of the cone so formed. (Take π = 3.14)
A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface of the cone so formed. (Take π = 3.14)

So the height of the resulting cone, h = 8 cm

Radius, r = 6 cm

Slant height, l = 10 cm

Volume of the cone, V = (1/3)r2h

V = (1/3)×3.14×62×8

V = (1/3)×3.14×36×8

V = 3.14×12×8

V = 301.44 cm3

Hence the volume of the cone is 301.44 cm3.

Curved surface area of the cone = rl

= 3.14×6×10

= 188.4

Hence the curved surface area of the cone is 188.4 cm2.