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Home » A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass.
A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass.
CBSE | Class 10 | Exercise 13.2 | Maths | NCERT | Surface Areas And Volumes
A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass.

Given, the tallness of the enormous chamber (H) = 220 cm

Sweep of the base (R)

    \[=\text{ }24/12\text{ }=\text{ }12\text{ }cm\]

Thus, the volume of the huge chamber = πR2H

    \[=\text{ }\pi \left( 12 \right)2\text{ }\times \text{ }220\text{ }cm3\]

    \[=\text{ }99565.8\text{ }cm3\]

Presently, the tallness of more modest chamber (h) = 60 cm

Sweep of the base (r) = 8 cm

Thus, the volume of the more modest chamber = πr2h

    \[=\text{ }\pi \left( 8 \right)2\times 60\text{ }cm3\]

    \[=\text{ }12068.5\text{ }cm3\]

∴ Volume of iron = Volume of the huge cylinder+ Volume of the little chamber

    \[=\text{ }99565.8\text{ }+\text{ }12068.5\]

    \[=111634.5\text{ }cm3\]

We know,

Mass = Density x volume

Thus, mass of the shaft

    \[=\text{ }8\times 111634.5\]

    \[=\text{ }893\text{ }Kg\text{ }\left( approx. \right)\]

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