A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k’. Then they are connected in parallel and force constant is k”. Then k’ : k” is
A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k’. Then they are connected in parallel and force constant is k”. Then k’ : k” is

(1) 1 : 9
(2) 1 : 11
(3) 1 : 14
(4) 1 : 6
Solution: Answer (2)

We know that the Spring constant (k) is inversely proportional to the length. So, we have:

k1 = 6k

k2 = 3k

k3 = 2k