Position of candle = 12.0 cm
Position of convex lens = 50.0 cm
Position of the screen = 88.0 cm
- What is the focal length of the convex lens?
- Where will the image be formed if he shifts the candle towards the lens at a position of 31.0 cm?
- What will be the nature of the image formed if he further shifts the candle towards the lens?
- Draw a ray diagram to show the formation of the image in case (iii) as said above.
Given,
Candle flame position = 12.0cm
Lens position= 50.0 cm
Screen position=88.0 cm
1. u= 50-12
u= 38 cm.
Image distance, v= 88-50
v= 38cm
Focal length =1/v – 1/u
Focal length = 1/f
f= 19cm
2. The distance of the object, u= 50-31
u= 19 cm
Object distance = focal length
Thus, the image is formed at infinity.
3. If he shifts the candle further towards the lens, the object comes between F and 0 and the image is virtual, enlarged and erect and is formed on the same side of the lens.
4.