Login/Sign Up
Home » A uniformly charged conducting sphere of diameter has a surface charge density of
A uniformly charged conducting sphere of 2.4 \mathrm{~m} diameter has a surface charge density of 80.0 \mu \mathrm{C} / \mathrm{m}^{2}
CBSE | Class 12 | Electric Charges and Fields | NCERT | Physics
A uniformly charged conducting sphere of 2.4 \mathrm{~m} diameter has a surface charge density of 80.0 \mu \mathrm{C} / \mathrm{m}^{2}

(a) Find the charge on the sphere.

(b) What is the total electric flux leaving the surface of the sphere?

Solution:

(a) Given: The diameter of the sphere, d=2.4 \mathrm{~m}

The radius of the sphere, r=1.2 \mathrm{~m}

You can figure out how much charge is on the surface of the sphere by doing the following:

=\sigma \times 4 \pi r^{2}
= 80 × 10^{-6} × 4 × 3.14 × 1.2 × 1.2

= 1.447 ×10^{-3} C

(b) Total is the total electric flux leaving off the surface of an inert sphere holding net charge Q, and it can be calculated using the equation

\phi_{\text {Total }}=\frac{Q}{\epsilon_{0}}

Here,

\epsilon_{0}= permittivity of free space =8.854 \times 10^{-12} \mathrm{~N}^{-1} \mathrm{C}^{2} \mathrm{~m}^{-2}
Substituting the value of given parameters and evaluating we will have the value of electric flux.

Therefore, the total electric flux leaving the surface of the sphere is 1.63 \times 10^{8} \mathrm{~N} \mathrm{C}^{-1} \mathrm{~m}^{2}

i

More Material