Solution:
Consider AB as the tower
Take a man C stands at a distance x m from the foot of the tower
cos θ = 0.53
We know that
Height of the tower AB = 20 m
cos θ = 0.53
So we get
θ = 580
Let us take
tan θ = AB/CB
Substituting the values
tan 580 = 20/x
So we get
1.6003 = 20/x
By cross multiplication
x = 20/1.6003
x = 12.49 = 12.5 m
Hence, the height of the tower is 12.5 m.