Consider TR as the total height of the tree
TP as the broken part which touches the ground at a distance of 6 m from the foot of the tree which makes an angle of 380 30’ with the ground
Take PR = x and TR = x + y
PQ = PT = y
In right triangle PQR
tan θ = PR/QR
Substituting the values
tan 380 30’ = x/6
x/6 = 0.7954
By cross multiplication
x = 0.7954 × 6 = 4.7724
We know that
sin θ = PR/PQ
Substituting the values
sin 380 30’ = x/y
So we get
0.6225 = 4.7724/y
y = 4.7724/0.6225 = 7.6665
Here
Height of the tree = 4.7724 + 7.6665 = 12.4389 = 12.44m
Height of the tree at which it is broken = 4.77 m