Given height of the cone, h = 20 cm
Diameter of the cone = 16.8 cm
Radius of the cone, r = 16.8/2 = 8.4 cm
Volume of water in the vessel = (1/3)r2h
= (1/3)×8.42 ×20
= (1/3)×(22/7)×8.4 ×8.4 ×20
= 1478.4 cm3
One third of volume of water in the vessel = (1/3)× 1478.4
= 492.8 cm3
One third of volume of water in the vessel = Volume of water over flown
Volume of water over flown = volume of two equal solid cones dropped into the vessel.
volume of two equal solid cones dropped into the vessel = 492.8 cm3
Volume of one solid cone dropped into the vessel = 492.8/2 = 246.4 cm3
Hence the volume of each of the solid cone submerged is 246.4 cm3.