Solution;

Given inner diameter of the well = 6 m

Radius of the well, r = 6/2 = 3 m

Depth of the well, H = 22 m

Volume of the soil dug out of well = r²H

= ×3²×22

= 198 m³

Width of the embankment = 5 m

Inner radius of embankment, r = 3 m

Outer radius of embankment, R = 3+5 = 8 m

Let h be height of the soil embankment.

Volume of the soil embankment = (R²– r²)h

= (8²– 3²)h

= (64-9)h

= 55h

Volume of the soil dug out = volume of the soil embankment

198 = 55h

h = 198/55

h = 3.6 m

Hence the height of the soil embankment is 3.6 m.