Let the woman’s reduced weight as x.
the original weight = 84 kg
So, we have
![\[\begin{array}{*{35}{l}} 84:\text{ }x\text{ }=\text{ }7:\text{ }5 \\ 84/x\text{ }=\text{ }7/5 \\ 84\text{ * }5\text{ }=\text{ }7x \\ x\text{ }=\text{ }\left( 84\text{ * }5 \right)/\text{ }7 \\ x\text{ }=\text{ }60 \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-a0fcea3863894a5141d5b023a38fc6e9_l3.png "Rendered by QuickLaTeX.com")
Therefore, the reduced weight of the woman is 60 kg.
A woman reduces her weight in the ratio 7: 5. What does her weight become if originally it was 84 kg?
A woman reduces her weight in the ratio 7: 5. What does her weight become if originally it was 84 kg?
and 
, internal resistance 
and 
, connected in parallel. The equivalent emf of the combination is- (A) 
(B) 
(C) 
(D) 
and 
are collinear, prove that 
and 
be three points such that area of a 
is 4 sq units, find the value of 
.
and 
is 35 sq units.
and 
are collinear.
and 
are collinear.
and 
are collinear.
and 