ABCD is a quadrilateral in which AD = BC. If P, Q, R, S be the midpoints of AB, AC, CD and BD respectively, show that PQRS is a rhombus.
ABCD is a quadrilateral in which AD = BC. If P, Q, R, S be the midpoints of AB, AC, CD and BD respectively, show that PQRS is a rhombus.

 

 

 

 

Answer:

In ∆ ABC, P and Q are mid points of AB and AC respectively.

So, PQ || BC, and PQ = \begin{array}{l}  \frac{{1}}{{2}}  \end{array}

???????? …(1)

Similarly, in ∆ADC, …(2)

Now, in ∆BCD, SR = \begin{array}{l}  \frac{{1}}{{2}}  \end{array}

???????? …(3)

In ∆ABD,

PS = \frac{1}{2}AD = \frac{1}{2}BC......(4)

With (1), (2), (3), and (4).

PQ = QR = SR = PS

All sides are equal

Therefore, PQRS is a rhombus.