An aeroplane leaves an airport and flies due north at a speed of 1000km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1200 km per hour. How far apart will be the two planes after 1\frac{1}{2} hours?
An aeroplane leaves an airport and flies due north at a speed of 1000km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1200 km per hour. How far apart will be the two planes after 1\frac{1}{2} hours?

 

 

 

 

 

Answer:

Let A be the first aeroplane flied due north at a speed of 1000 km/hr and B be the second aeroplane flied due west at a speed of 1200 km/hr

Distance covered by plane A in 1\frac{1}{2} ℎ???????????????? = 1000 × \frac{3}{2} => 1500 ????????

Distance covered by plane B in 1\frac{1}{2} ℎ???????????????? = 1200 × \frac{3}{2} => 1800 ????????

In right triangle ABC,

By using Pythagoras theorem,

????????2 = ????????2 + ????????2

=> (1800) 2 + (1500) 2

=> 3240000 + 2250000

=> 5490000

=> 5490000

AB = 300 √61 ????

Therefore, the distance between two planes after 1\frac{1}{2} ℎ???????????????? ???????? 300 √61m.