Since, the tallness and width of the circular segment from the middle is
![\[2m\text{ }and\text{ }8m\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-e35dd1d426b8adc24dcffce59f4a11b6_l3.png "Rendered by QuickLaTeX.com")
separately, obviously the length of the significant hub is
![\[8m\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-9495c1f95319594f4ff6d70132160d6f_l3.png "Rendered by QuickLaTeX.com")
, while the length of the semi-minor hub is
![\[2m.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-1bad119fb48d5be31145500680901c18_l3.png "Rendered by QuickLaTeX.com")
The beginning of the organize plane is taken as the focal point of the oval, while the significant pivot is brought the
![\[x-hub\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-0d4d5899d8442a83de4f0f1666db04c8_l3.png "Rendered by QuickLaTeX.com")
.
Consequently, Diagrammatic portrayal of semi-circle is as per the following:
The condition of the semi – ellipse will be of the from
![\[x2/16\text{ }+\text{ }y2/4\text{ }=\text{ }1,\text{ }y\text{ }\ge \text{ }0\text{ }\ldots \text{ }(1)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-ced9dbc30638d7fbc95b3a951f49d8e8_l3.png "Rendered by QuickLaTeX.com")
Leave An alone a point on the significant hub with the end goal that
![\[AB\text{ }=\text{ }1.5m.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-1c1e73589769f4d32121d2ca2fd836d6_l3.png "Rendered by QuickLaTeX.com")
Presently draw
![\[AC\bot OB.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-07987084d04909b2c13825424ae8f5fd_l3.png "Rendered by QuickLaTeX.com")
![\[OA\text{ }=\text{ }\left( 4\text{ }\text{ }1.5 \right)m\text{ }=\text{ }2.5m\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-72ad4c055be6b37d19f2efb11abb61be_l3.png "Rendered by QuickLaTeX.com")
The x – coordinate of point
![\[C\text{ }is\text{ }2.5\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-1f5fd87e334e84bf69258f1c9d418777_l3.png "Rendered by QuickLaTeX.com")
On subbing the worth of
![\[x\text{ }with\text{ }2.5\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-2e0e4a2ea9eb5bb8f08e1fcf16bf428c_l3.png "Rendered by QuickLaTeX.com")
in condition
![\[\left( 1 \right),\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-6ab88eefb94fe80e32a489967e1f88eb_l3.png "Rendered by QuickLaTeX.com")
we get,
![\[<span class="ql-right-eqno"> (1) </span><span class="ql-left-eqno"> </span><img src="https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-fb08726048063e3e2fe8be83f4395249_l3.png" height="284" width="326" class="ql-img-displayed-equation quicklatex-auto-format" alt="\begin{align*} & \begin{array}{*{35}{l}} {{\left( 2.5 \right)}^{2}}/16\text{ }+\text{ }{{y}^{2}}/4\text{ }=\text{ }1 \\ 6.25/16\text{ }+\text{ }{{y}^{2}}/4\text{ }=\text{ }1 \\ {{y}^{2}}~=\text{ }4\text{ }\left( 1\text{ }\text{ }6.25/16 \right) \\ \end{array} \\ & \begin{array}{*{35}{l}} =\text{ }4\text{ }\left( 9.75/16 \right) \\ =\text{ }2.4375 \\ y\text{ }=\text{ }1.56\text{ }\left( approx. \right) \\ So,\text{ }AC\text{ }=\text{ }1.56m \\ \end{array} \\ \end{align*}" title="Rendered by QuickLaTeX.com"/>\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-a99b5691c630d70fb5c37adf5697bf27_l3.png "Rendered by QuickLaTeX.com")
Consequently, the stature of the curve at a point
![\[1.5m\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-523076c144fd779210f1a4c1c0f67b22_l3.png "Rendered by QuickLaTeX.com")
from one end is roughly
![\[1.56m.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-0f971ca1cb9b75711b9fff22c7f3d9de_l3.png "Rendered by QuickLaTeX.com")