An electric heater supplies heat to a system at a rate of 100W. If system performs work at a rate of 75 joules per second. At what rate is the internal energy increasing?
An electric heater supplies heat to a system at a rate of 100W. If system performs work at a rate of 75 joules per second. At what rate is the internal energy increasing?

Given:

As we know that the law of conservation of energy states that all energy is conserved.
The total energy is equal to the sum of work done and internal energy.
ΔQ = ΔW + ΔU

Heating at a rate of 100 W is referred to as Q.

The rate at which something is completed W = 75 J/s is the unit of energy.

The rate of change of internal energy is denoted by the symbol ΔU.

ΔU = ΔQ – ΔW

ΔU = 100 – 75

We get,

ΔU = 25 J s-1

Hence,

The internal energy of the system is increasing at a rate of 25 W