Login/Sign Up
Home » Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one die and squares the number that appears on it. Who has the better chance of getting the number 36? Why?
Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one die and squares the number that appears on it. Who has the better chance of getting the number 36? Why?
CBSE | Class 10 | Exercise 13.2 | Maths | NCERT Exemplar | Statistics and Probability
Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one die and squares the number that appears on it. Who has the better chance of getting the number 36? Why?

Apoorv toss two dice on the double.

Thus, the all out number of results = 36

Number of results for getting item 36 = 1(6×6)

∴ Probability for Apoorv = 1/36

Peehu tosses one kick the bucket,

Thus, the all out number of results = 6

Number of results for getting square = 36

∴ Probability for Peehu = 6/36 = 1/6

Thusly, Peehu has a superior shot at getting the number 36.

i

More Material