Considering L.H.S : Getting terms c – b cos A and b – c cos A from projection formula Using projection formula, \[c\text{ }=\text{ }a\text{ }cos\text{ }B\text{ }+\text{ }b\text{ }cos\text{...

Considering L.H.S : \[({{c}^{2}}~\text{ }{{a}^{2}}~+\text{ }{{b}^{2}}),\text{ }({{a}^{2}}~\text{ }{{b}^{2}}~+\text{ }{{c}^{2}}),\text{ }({{b}^{2}}~\text{ }{{c}^{2}}~+\text{ }{{a}^{2}})\] Using sine...

Considering L.H.S : \[2\text{ }\left( bc\text{ }cos\text{ }A\text{ }+\text{ }ca\text{ }cos\text{ }B\text{ }+\text{ }ab\text{ }cos\text{ }C \right)\] \[2ca\text{ }cos\text{ }B,\text{ }2ab\text{...

Considering L.H.S. \[c\text{ }\left( a\text{ }cos\text{ }B\text{ }\text{ }b\text{ }cos\text{ }A \right)\] \[ca\text{ }cos\text{ }B\text{ }and\text{ }cb\text{ }cos\text{ }A\] is present in L.H.S,...

So, considering LHS: \[b\text{ }\left( c\text{ }cos\text{ }A\text{ }\text{ }a\text{ }cos\text{ }C \right)\] \[bc\text{ }cos\text{ }A\text{ }and\text{ }ab\text{ }cos\text{ }C\]are L.H.S, which can be...

ACCORDING TO QUES,: Sides of a triangle are \[a\text{ }=\text{ }18,\text{ }b\text{ }=\text{ }24\text{ }and\text{ }c\text{ }=\text{ }30\] Hence, using the formulas: \[Cos\text{ }A\text{ }=\text{...

ACCORDING TO QUES,: Sides of the triangle: \[a\text{ }=\text{ }4,\text{ }b\text{ }=\text{ }6\text{ }and\text{ }c\text{ }=\text{ }8\] By using the formulas, \[Cos\text{ }A\text{ }=\text{...

According to the given ques: In \[\vartriangle ABC,\text{ }a\text{ }=\text{ }\surd 2,\text{ }b\text{ }=\text{ }\surd 3\text{ }and\text{ }c\text{ }=\text{ }\surd 5~\] Hence, using the formulas,...

ACCORDING TO QUES: In a \[\vartriangle ABC,\text{ }a\text{ }=\text{ }5,\text{ }b\text{ }=\text{ }6\text{ }and\text{ }C\text{ }=\text{ }{{60}^{o}}\] By using the formula, Area of\[\vartriangle...

on simplification we have, \[\begin{array}{*{35}{l}} =\text{ }{{k}^{2}}~[sin\text{ }A\text{ }sin\text{ }\left( B\text{ }\text{ }C \right)\text{ }+\text{ }sin\text{ }B  \\ sin\text{ }\left( C\text{...

according to sine rule, \[a\text{ }=\text{ }k\text{ }sin\text{ }A,\] \[~b\text{ }=\text{ }k\text{ }sin\text{ }B,\] \[c\text{ }=\text{ }k\text{ }sin\text{ }C\] Let LHS: \[a\text{ }\left( sin\text{...

according to the ques, now, equals RHS, hence proved.

According to sine rule, now, \[~c\text{ }=\text{ }k\text{ }sin\text{ }C\] same way, \[a\text{ }=\text{ }k\text{ }sin\text{ }A\] also, \[b\text{ }=\text{ }k\text{ }sin\text{ }B\] As we know, Now let...

according to sine rule, Now, \[~c\text{ }=\text{ }k\text{ }sin\text{ }C\] In the same way, \[a\text{ }=\text{ }k\text{ }sin\text{ }A\] also, \[~b\text{ }=\text{ }k\text{ }sin\text{ }B\] As we know,...

According to the given equation we can use sine rule, now,    

according to sine rule, now,

According to sine rule,  

according to sine rule, \[cos\text{ }\left( A\text{ }+\text{ }B \right)/2\text{ }=\text{ }cos\text{ }\left( A/2\text{ }+\text{ }B/2 \right)\text{ }=\text{ }cos\text{ }A/2\text{ }cos\text{ }B/2\text{...

according to sine rule,

according to sine rule, equals RHS. Hence proved.

according to sine rule,

According to ques, : In ∆ABC,  \[\angle C\text{ }=\text{ }{{105}^{o}},\] \[~\angle B\text{ }=\text{ }{{45}^{o}},\] \[~a\text{ }=\text{ }2\] Since, \[\angle A\text{ }+~\angle B\text{ }+~\angle...

according to sine rule, \[a:\text{ }b:\text{ }c\text{ }=\text{ }2:\text{ }\surd 6:\text{ }\left( 1+\surd 3 \right)\] Therefore, the ratio of the sides of the given triangle is: \[~a:\text{ }b:\text{...