Solutions:

Provided here that,

The Third term, a₃ = 16

As we all know,

a +(3−1)d = 16

a+2d = 16 ………………………………………. (i)

It is known that, 7^th term exceeds the 5^th term by 12.

a₇ − a₅ = 12

[a+(7−1)d]−[a +(5−1)d]= 12

(a+6d)−(a+4d) = 12

2d = 12

d = 6

From equation (i), we get,

a+2(6) = 16

a+12 = 16

a = 4

As a result, A.P. will be 4, 10, 16, 22,…