Solution:-
From the dimensions given in the question,
Consider the ∆PQR
So, PQ/PE = 1.28/0.18
= 128/18
= 64/9
Then, PR/PF = 2.56/0.36
= 256/36
= 64/9
By comparing both the results,
64/9 = 64/9
Therefore, PQ/PE = PR/PF
So, EF is parallel to QR.