If sin A = ½ , then the value of cot A is
 If sin A = ½ , then the value of cot A is

(A) √3 (B) 1/√3 (C) √3/2 (D) 1

(A) √3

As indicated by the inquiry,

    \[Sin\text{ }A\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\text{ }\ldots \text{ }\left( 1 \right)\]

We realize that,

NCERT Exemplar Class 10 Maths Chapter 8 Ex. 8.1 Question 2 … (2)

To discover the worth of cos A.

We have the condition,

    \[sin2\text{ }\theta \text{ }+cos2\text{ }\theta \text{ }=1\]

In this way,

    \[cos\text{ }\theta \text{ }=\text{ }\surd \left( 1-sin2\text{ }\theta  \right)\]

Then, at that point,

    \[cos\text{ }A\text{ }=\text{ }\surd \left( 1-sin2\text{ }A \right)\text{ }\ldots \text{ }\left( 3 \right)\]

    \[cos2\text{ }A\text{ }=\text{ }1-sin2\text{ }A\]

    \[cos\text{ }A\text{ }=\text{ }\surd \text{ }\left( 1-sin2\text{ }A \right)\]

Subbing condition 1 of every 3, we get,

    \[cos\text{ }A\text{ }=\text{ }\surd \left( 1-1/4 \right)\text{ }=\text{ }\surd \left( 3/4 \right)\text{ }=\text{ }\surd 3/2\]

Subbing upsides of transgression An and cos An in condition 2, we get

bunk A = (√3/2) × 2 = √3