Find the coordinates of the centre radius of each of the following circle: (iii) \frac{1}{2}({{x}^{2}}+{{y}^{2}})+x\cos \theta +y\sin \theta -4=0 (iv) {{x}^{2}}+{{y}^{2}}-ax-by=0
Find the coordinates of the centre radius of each of the following circle: (iii) \frac{1}{2}({{x}^{2}}+{{y}^{2}})+x\cos \theta +y\sin \theta -4=0 (iv) {{x}^{2}}+{{y}^{2}}-ax-by=0

RD Sharma Solutions for Class 11 Maths Chapter 24 – The Circle - image 14

The equation of the circle is

RD Sharma Solutions for Class 11 Maths Chapter 24 – The Circle - image 15

(Multiply by 2 we get)

    \[\begin{array}{*{35}{l}} {{x}^{2}}~+\text{ }{{y}^{2}}~+\text{ }2x\text{ }cos\text{ }\theta \text{ }+\text{ }2y\text{ }sin\text{ }\theta \text{ }-\text{ }8\text{ }=\text{ }0  \\ {{x}^{2}}~+\text{ }{{y}^{2}}~+\text{ }2ax\text{ }+\text{ }2by\text{ }+\text{ }c\text{ }=\text{ }0  \\ Centre\text{ }=\text{ }\left( -a,\text{ }-b \right)  \\ =\text{ }\left[ \left( -2cos\text{ }\theta  \right)/2\text{ },\text{ }\left( -2sin\text{ }\theta  \right)/2 \right]  \\ =\text{ }\left( -cos\text{ }\theta ,\text{ }-sin\text{ }\theta  \right)  \\ Radius\text{ }=~\surd \left( {{a}^{2}}~+\text{ }{{b}^{2}}~-\text{ }c \right)  \\ =\text{ }\surd \left[ {{\left( -cos\text{ }\theta  \right)}^{2}}~+\text{ }{{\left( sin\text{ }\theta  \right)}^{2}}~\text{ }\left( -8 \right) \right]  \\ =\text{ }\surd \left[ co{{s}^{2}}~\theta \text{ }+\text{ }si{{n}^{2}}~\theta \text{ }+\text{ }8 \right]  \\ =\text{ }\surd \left[ 1\text{ }+\text{ }8 \right]  \\ =\text{ }\surd \left[ 9 \right]  \\ =\text{ }3  \\ \end{array}\]

∴ The centre and radius of the circle is (-cos θ, -sin θ) and 3.

(iv) x2 + y2 – ax – by = 0

Equation of the circle is

    \[\begin{array}{*{35}{l}} {{x}^{2}}~+\text{ }{{y}^{2}}~-\text{ }ax\text{ }-\text{ }by\text{ }=\text{ }0  \\ ~{{x}^{2}}~+\text{ }{{y}^{2}}~+\text{ }2ax\text{ }+\text{ }2by\text{ }+\text{ }c\text{ }=\text{ }0  \\ Centre\text{ }=\text{ }\left( -a,\text{ }-b \right)  \\ =\text{ }-\left( -\left( -a \right)/2,\text{ }-\left( -b \right)/2 \right)  \\ =\text{ }\left( a/2,\text{ }b/2 \right)  \\ Radius\text{ }=~\surd \left( {{a}^{2}}~+\text{ }{{b}^{2}}~-\text{ }c \right)  \\ =\text{ }\surd \left[ {{\left( a/2 \right)}^{2}}~+\text{ }{{\left( b/2 \right)}^{2}} \right]  \\ =~\surd \left[ \left( {{a}^{2}}/4\text{ }+\text{ }{{b}^{2}}/4 \right) \right]  \\ =~\surd \left[ \left( {{a}^{2}}~+\text{ }{{b}^{2}} \right)/4 \right]  \\ =\text{ }\left[ \surd \left( {{a}^{2}}~+\text{ }{{b}^{2}} \right) \right]/2  \\ \end{array}\]

∴ The centre and radius of the circle is (a/2, b/2) and [(a2 + b2)]/2