Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse.

    \[\mathbf{4}{{\mathbf{x}}^{\mathbf{2}}}~+\text{ }\mathbf{9}{{\mathbf{y}}^{\mathbf{2}}}~=\text{ }\mathbf{36}\]

Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse.

    \[\mathbf{4}{{\mathbf{x}}^{\mathbf{2}}}~+\text{ }\mathbf{9}{{\mathbf{y}}^{\mathbf{2}}}~=\text{ }\mathbf{36}\]

Given:

The condition is

    \[4{{x}^{2}}~+\text{ }9{{y}^{2}}~=\text{ }36\text{ }or\text{ }{{x}^{2}}/9\text{ }+\text{ }{{y}^{2}}/4\text{ }=\text{ }1\text{ }or\text{ }{{x}^{2}}/{{3}^{2}}~+\text{ }{{y}^{2}}/{{2}^{2}}~=\text{ }1\]

Here, the denominator of

    \[{{x}^{2}}/{{3}^{2}}\]

is more noteworthy than the denominator of

    \[{{y}^{2}}/{{2}^{2}}.\]

Thus, the significant pivot is along thex-axis, while the minor hub is along they-axis.

On contrasting the given condition and

    \[{{x}^{2}}/{{a}^{2}}~+\text{ }{{y}^{2}}/{{b}^{2}}~=\text{ }1,\]

we get

    \[\begin{array}{*{35}{l}} a\text{ }=3\text{ }and\text{ }b\text{ }=2.  \\ c\text{ }=\text{ }\surd \left( {{a}^{2}}~\text{ }{{b}^{2}} \right)  \\ =\text{ }\surd \left( 9-4 \right)  \\ =\text{ }\surd 5  \\ \end{array}\]

Then, at that point,

The directions of the foci are

    \[\left( \surd 5,\text{ }0 \right)\text{ }and\text{ }\left( -\surd 5,\text{ }0 \right).\]

The directions of the vertices are

    \[\left( 3,\text{ }0 \right)\text{ }and\text{ }\left( -3,\text{ }0 \right)\]

    \[\begin{array}{*{35}{l}} Length\text{ }of\text{ }major\text{ }axis\text{ }=\text{ }2a\text{ }=\text{ }2\text{ }\left( 3 \right)\text{ }=\text{ }6  \\ Length\text{ }of\text{ }minor\text{ }axis\text{ }=\text{ }2b\text{ }=\text{ }2\text{ }\left( 2 \right)\text{ }=\text{ }4  \\ Eccentricity,\text{ }e\text{ }=\text{ }c/a~=\text{ }\surd 5/3  \\ Length of latus rectum \[=\text{ }2{{b}^{2}}/a\text{ }=\text{ }(2\times {{2}^{2}})/3\text{ }=\text{ }\left( 2\times 4 \right)/3\text{ }=\text{ }8/3\]

8/3