Find the coordinates of the focus and the vertex, the equations of the directrix and the axis, and length of the latus rectum of the parabola : {y^2} = -6x
Find the coordinates of the focus and the vertex, the equations of the directrix and the axis, and length of the latus rectum of the parabola : {y^2} = -6x

Answer:

 

 

 

 

 

Given,

y2 = -6x

Comparing given equation with parabola having equation,

y2 = – 4ax

4a = 6

a = 2/3

Focus: F(-a, 0) = F(-2/3, 0)

Vertex: A(0, 0) =A(0, 0)

Equation of the directrix:

x – a = 0

x – 3/2 = 0

x = 3/2

Length of latus rectum: 4a = 6