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Find the coordinates of the focus and the vertex, the equations of the directrix and the axis, and length of the latus rectum of the parabola : {5y^2} = -16x
CBSE | Class 11 | Exercise 22 | Maths | Parabola | RS Aggarwal
Find the coordinates of the focus and the vertex, the equations of the directrix and the axis, and length of the latus rectum of the parabola : {5y^2} = -16x

Answer:

 

 

 

 

Given,

5y2 = -16x

y2 = -16/5 x

Comparing the given equation with parabola having an equation,

y2 = – 4ax

4???? = 16/5

???? = 4/5

Focus : F(-a,0) = F(-4/5, 0)

Vertex : A(0,0) = A(0,0)

Equation of the directrix :

x – a = 0

x – 4/5 = 0

x = 4/5

Length of latus rectum: 4a = 16/5

 

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