Find the equation for the ellipse that satisfies the given conditions: Major axis on the x-axis and passes through the points (4,3) and (6,2).
Find the equation for the ellipse that satisfies the given conditions: Major axis on the x-axis and passes through the points (4,3) and (6,2).

Solution:-

Given:

Major axis on the x-axis and passes through the points (4, 3) and (6, 2).

Since the major axis is on the x-axis, the equation of the ellipse will be the form
\mathrm{x}^{2} / \mathrm{a}^{2}+\mathrm{y}^{2} / \mathrm{b}^{2}=1 \ldots(1)\left[\right. Where ‘ \mathrm{a}^{3} is the semi-major axis.]
The ellipse passes through points (4,3) and (6,2)
So by putting the values x=4 and y=3 in equation (1), we get, 16 / a^{2}+9 / b^{2}=1 \ldots(2)
Putting, x=6 and y=2 in equation (1), we get,

36 / a^{2}+4 / b^{2}=1 \ldots . \text { (3) }

From equation (2)

\begin{array}{l} 16 / a^{2}=1-9 / b^{2} \\ 1 / a^{2}=\left(1 / 16\left(1-9 / b^{2}\right)\right) \ldots .(4) \end{array}

Substituting the value of 1 / \mathrm{a}^{2} in equation (3) we get,

\begin{array}{l} 36 / a^{2}+4 / b^{2}=1 \\ 36\left(1 / a^{2}\right)+4 / b^{2}=1 \\ 36\left[1 / 16\left(1-9 / b^{2}\right)\right]+4 / b^{2}=1 \\ 36 / 16\left(1-9 / b^{2}\right)+4 / b^{2}=1 \\ 9 / 4\left(1-9 / b^{2}\right)+4 / b^{2}=1 \\ 9 / 4-81 / 4 b^{2}+4 / b^{2}=1 \\ -81 / 4 b^{2}+4 / b^{2}=1-9 / 4 \\ (-81+16) / 4 b^{2}=(4-9) / 4 \\ -65 / 4 b^{2}=-5 / 4 \\ -5 / 4\left(13 / b^{2}\right)=-5 / 4 \\ 13 / b^{2}=1 \\ 1 / b^{2}=1 / 13 \\ b^{2}=13 \end{array}

Now substitute the value of b^{2} in equation (4) we get,

\begin{array}{l} 1 / a^{2}=1 / 16\left(1-9 / b^{2}\right) \\ =1 / 16(1-9 / 13) \\ =1 / 16((13-9) / 13) \\ =1 / 16(4 / 13) \\ =1 / 52 \\ a^{2}=52 \end{array}

Equation of ellipse is x^{2} / a^{2}+y^{2} / b^{2}=1
By substituting the values of a^{2} and b^{2} in above equation we get, x^{2} / 52+y^{2} / 13=1