Find the equation for the ellipse that satisfies the given conditions: Vertices (0, ± 13), foci (0, ± 5)
Find the equation for the ellipse that satisfies the given conditions: Vertices (0, ± 13), foci (0, ± 5)

Given:

    \[Vertices\text{ }\left( 0,~\pm ~13 \right)\text{ }and\text{ }foci\text{ }\left( 0,~\pm \text{ }5 \right)\]

Here, the vertices are on the

    \[x-pivot.\]

Along these lines, the condition of the circle will be of the structure

    \[{{x}^{2}}/{{b}^{2}}~+\text{ }{{y}^{2}}/{{a}^{2}}~=\text{ }1,~\]

, where ‘a’ is the semi-significant pivot.

Then, at that point,

    \[a\text{ }=13\text{ }and\text{ }c\text{ }=\text{ }5.\]

It is realized that

    \[{{a}^{2}}~=\text{ }{{b}^{2~}}+\text{ }{{c}^{2}}.\]

    \[{{13}^{2}}~=\text{ }{{b}^{2}}+{{5}^{2}}\]

    \[169\text{ }=\text{ }{{b}^{2}}~+\text{ }15\]

    \[{{b}^{2}}~=\text{ }169\text{ }\text{ }125\]

    \[b\text{ }=~\surd 144\]

    \[=\text{ }12\]

∴ The condition of the circle is

    \[{{x}^{2}}/{{12}^{2}}~+\text{ }{{y}^{2}}/{{13}^{2}}~=\text{ }1\text{ }or\text{ }{{x}^{2}}/144\text{ }+\text{ }{{y}^{2}}/169~=\text{ }1\]