Solution:

Given line: 3x – 2y = -4

Slope (m₁) is given by

2y = 3x + 4

y = (3/2) x + 2

So, m₁ = 3/2

Now, the slope of the line parallel to the given line will have the same slope as 3/2 = m

And the line passes through point (0, 3)

Thus, the equation of the required line is given by

y = mx + c

y = (3/2) x + 3

2y = 3x + 6

3x – 2y + 6 = 0