Find the equation of the parallel to x–axis and passing through (3, –5).
Find the equation of the parallel to x–axis and passing through (3, –5).

Given: A line which is parallel to

    \[x-axis\]

and passing through

    \[\left( 3,-\text{ }5 \right)\]

By using the formula,

The equation of line:

    \[[y\text{ }-\text{ }{{y}_{1}}~=\text{ }m(x\text{ }-\text{ }{{x}_{1}})]\]

We know that the parallel lines have equal slopes

And, the slope of

    \[x-axis\]

is always

    \[0\]

Then

The slope of line,

    \[m\text{ }=\text{ }0\]

Coordinates of line are

    \[({{x}_{1}},\text{ }{{y}_{1}})\text{ }=\text{ }\left( 3,-\text{ }5 \right)\]

The equation of line

    \[=\text{ }y\text{ }-\text{ }{{y}_{1}}~=\text{ }m(x\text{ }-\text{ }{{x}_{1}})\]

Now, substitute the values, we get

    \[y\text{ }-\text{ }\left( -\text{ }5 \right)\text{ }=\text{ }0\left( x\text{ }-\text{ }3 \right)\]

    \[y\text{ }+\text{ }5\text{ }=\text{ }0\]

∴ The equation of line is

    \[y\text{ }+\text{ }5\text{ }=\text{ }0\]